document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=191480>Question 191480</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me with this one?  \r<BR>\n" );
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document.write( "Solve by substitution.  Determine if the equation is dependent, independent or inconsistant.\r<BR>\n" );
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document.write( "y = -3x + 19<BR>\n" );
document.write( "y = 2x -1\r<BR>\n" );
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document.write( "I'm not sure if I'm doing this right. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143694 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143694\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = -3x + 19.........eq 1<BR>\n" );
document.write( "y = 2x -1............eq 2<BR>\n" );
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document.write( "take the value of y from eq 2 and plug it into eq 1<BR>\n" );
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document.write( "2x-1=-3x+19<BR>\n" );
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document.write( "5x=20<BR>\n" );
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document.write( "x=4<BR>\n" );
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document.write( "now take x's found value and plug it into either equationa and solve for y. I will use eq 2<BR>\n" );
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document.write( "y=2(4)-1=7<BR>\n" );
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document.write( "(4,7) is the solution meaning this is a consistent and independent system since the is one a only one solution <BR>\n" );
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