document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26497>Question 26497</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do i do this question:\r<BR>\n" );
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document.write( "(x-2)(x+3)/(x-4) > 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14368 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14368\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x-2)(x+3)/(x-4) > 0<BR>\n" );
document.write( "FOR A FRACTION TO BE POSITIVE ,BOTH N.R AND D.R SHOULD BE POSTIVE OR NEGATIVE<BR>\n" );
document.write( "CASE I....N.R AND D.R POSITIVE<BR>\n" );
document.write( "FOR PRODUCT OF 2 FACTORS TO BE POSITIVE BOTH SHOUD BE POSITIVE OR NEGATIVE.<BR>\n" );
document.write( "VARIANT I<BR>\n" );
document.write( "X-2,X+3 ARE POSITIVE.SO X>2..D.R=X-4....X-4>0...SO X>4<BR>\n" );
document.write( "THAT IS IN THIS CASE X>4<BR>\n" );
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document.write( "VARIANT II<BR>\n" );
document.write( "X-2,X+3 ARE NEGATIVE.SO X<-3....D.R=X-4.....X-4>0...SO X>4...THIS IS NOT POSSIBLE<BR>\n" );
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document.write( "SO UNDER CASE I,THE ONLY POSSIBILITY IS X>4<BR>\n" );
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document.write( "CASE II........N.R AND D.R NEGATIVE.........<BR>\n" );
document.write( "FOR PRODUCT OF 2 FACTORS TO BE NEGATIVE ONE SHOUD BE POSITIVE AND ANOTHER NEGATIVE.<BR>\n" );
document.write( "SO X SHOULD BE BETWEEN 2 AND -3....AND D.R=X-4<0...X<4<BR>\n" );
document.write( "SO X IS BETWEEN 2 AND -3\r<BR>\n" );
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document.write( "hence the total solution set is for <BR>\n" );
document.write( "x to be greater than 4 or between 2 and -3. </SPAN>\n" );
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