document.write( "Question 191403: please help factor out polynomial.
\n" ); document.write( "
\n" ); document.write( "14x^3y+21x^2y^2-35xy^3
\n" ); document.write( "
\n" ); document.write( "thanksPeacee \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "--Kyle
\n" ); document.write( "

Algebra.Com's Answer #143646 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "\"14x%5E3y%2B21x%5E2y%5E2-35xy%5E3\" Start with the given expression\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"7xy%282x%5E2%2B3xy-5y%5E2%29\" Factor out the GCF \"7xy\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now let's focus on the inner expression \"2x%5E2%2B3xy-5y%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "------------------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Looking at \"2x%5E2%2B3xy-5y%5E2\" we can see that the first term is \"2x%5E2\" and the last term is \"-5y%5E2\" where the coefficients are 2 and -5 respectively.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 2 and the last coefficient -5 to get -10. Now what two numbers multiply to -10 and add to the middle coefficient 3? Let's list all of the factors of -10:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Factors of -10:\r
\n" ); document.write( "\n" ); document.write( "1,2,5,10\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-1,-2,-5,-10 ...List the negative factors as well. This will allow us to find all possible combinations\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to -10\r
\n" ); document.write( "\n" ); document.write( "(1)*(-10)\r
\n" ); document.write( "\n" ); document.write( "(2)*(-5)\r
\n" ); document.write( "\n" ); document.write( "(-1)*(10)\r
\n" ); document.write( "\n" ); document.write( "(-2)*(5)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "note: remember, the product of a negative and a positive number is a negative number\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 3? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "
First NumberSecond NumberSum
1-101+(-10)=-9
2-52+(-5)=-3
-110-1+10=9
-25-2+5=3
\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "From this list we can see that -2 and 5 add up to 3 and multiply to -10\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"2x%5E2%2B3xy-5y%5E2\", replace \"3xy\" with \"-2xy%2B5xy\" (notice \"-2xy%2B5xy\" adds up to \"3xy\". So it is equivalent to \"3xy\")\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2Bhighlight%28-2xy%2B5xy%29%2B-5y%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now let's factor \"2x%5E2-2xy%2B5xy-5y%5E2\" by grouping:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%282x%5E2-2xy%29%2B%285xy-5y%5E2%29\" Group like terms\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2x%28x-y%29%2B5y%28x-y%29\" Factor out the GCF of \"2x\" out of the first group. Factor out the GCF of \"5y\" out of the second group\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%282x%2B5y%29%28x-y%29\" Since we have a common term of \"x-y\", we can combine like terms\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"2x%5E2-2xy%2B5xy-5y%5E2\" factors to \"%282x%2B5y%29%28x-y%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So this also means that \"2x%5E2%2B3xy-5y%5E2\" factors to \"%282x%2B5y%29%28x-y%29\" (since \"2x%5E2%2B3xy-5y%5E2\" is equivalent to \"2x%5E2-2xy%2B5xy-5y%5E2\")\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "------------------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So our expression goes from \"7xy%282x%5E2%2B3xy-5y%5E2%29\" and factors further to \"7xy%282x%2B5y%29%28x-y%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "------------------\r
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"14x%5E3y%2B21x%5E2y%5E2-35xy%5E3\" completely factors to \"7xy%282x%2B5y%29%28x-y%29\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );