document.write( "Question 26498: I need help with this question, I have a few of the answers but need the rest.
\n" ); document.write( "Thanks Jeff
\n" ); document.write( "1) Use the arithmetic series of numbers 1, 3, 5, 7, 9,…to find the following:
\n" ); document.write( "a) What is d, the difference between any 2 terms?
\n" ); document.write( "Answer: 2
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\n" ); document.write( "1+2=3+2=5+2=7+2=9
\n" ); document.write( "b) Using the formula for the nth term of an arithmetic series, what is 101st term? Answer:
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\n" ); document.write( "\n" ); document.write( "c) Using the formula for the sum of an arithmetic series, what is the sum of the first 20 terms? 400
\n" ); document.write( "d) Answer:Show work in this space\r
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\n" ); document.write( "\n" ); document.write( "e) Using the formula for the sum of an arithmetic series, what is the sum of the first 30 terms?
\n" ); document.write( "Answer:
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Algebra.Com's Answer #14363 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The 1st term is a(1)=1
\n" ); document.write( "d is the difference between any two consecutive terms: e.g. d=3-1=2
\n" ); document.write( "The nth term is a(n)=a(1)+(n-1)d
\n" ); document.write( "The sum of n terms is S(n)=(1/2)n[a(1)+a(n)]
\n" ); document.write( "101st term: a(101)=a(1)+(100)d
\n" ); document.write( " =1+100*2=201
\n" ); document.write( "Sum of 1st 20 terms:
\n" ); document.write( "a(20)=1+(19)2=1+38=39
\n" ); document.write( "S(20)=(1/2)(20)(1+39)
\n" ); document.write( " =10(40)=400
\n" ); document.write( "Sum of 1st 30 terms:
\n" ); document.write( "a(30)=a(1)+29(2)
\n" ); document.write( " =1+58=59
\n" ); document.write( "S(30)=(1/2)(30)(1+59)
\n" ); document.write( " =15(60)
\n" ); document.write( " =900
\n" ); document.write( "Cheers,
\n" ); document.write( "stan H.
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