document.write( "Question 26498: I need help with this question, I have a few of the answers but need the rest.
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document.write( "Thanks Jeff
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document.write( "1) Use the arithmetic series of numbers 1, 3, 5, 7, 9,…to find the following:
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document.write( "a) What is d, the difference between any 2 terms?
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document.write( "Answer: 2
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document.write( "1+2=3+2=5+2=7+2=9
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document.write( "b) Using the formula for the nth term of an arithmetic series, what is 101st term? Answer:
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document.write( "c) Using the formula for the sum of an arithmetic series, what is the sum of the first 20 terms? 400
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document.write( "d) Answer:Show work in this space\r
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document.write( "e) Using the formula for the sum of an arithmetic series, what is the sum of the first 30 terms?
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document.write( "Answer:
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Algebra.Com's Answer #14363 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The 1st term is a(1)=1 \n" ); document.write( "d is the difference between any two consecutive terms: e.g. d=3-1=2 \n" ); document.write( "The nth term is a(n)=a(1)+(n-1)d \n" ); document.write( "The sum of n terms is S(n)=(1/2)n[a(1)+a(n)] \n" ); document.write( "101st term: a(101)=a(1)+(100)d \n" ); document.write( " =1+100*2=201 \n" ); document.write( "Sum of 1st 20 terms: \n" ); document.write( "a(20)=1+(19)2=1+38=39 \n" ); document.write( "S(20)=(1/2)(20)(1+39) \n" ); document.write( " =10(40)=400 \n" ); document.write( "Sum of 1st 30 terms: \n" ); document.write( "a(30)=a(1)+29(2) \n" ); document.write( " =1+58=59 \n" ); document.write( "S(30)=(1/2)(30)(1+59) \n" ); document.write( " =15(60) \n" ); document.write( " =900 \n" ); document.write( "Cheers, \n" ); document.write( "stan H. \n" ); document.write( " \n" ); document.write( " |