document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26141>Question 26141</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If each side of a square were increased by 4in., the perimeter would be 8 in. less than twice the perimeter of the orginal square. Find the length of a side of the orginal square. \r<BR>\n" );
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document.write( "One squeare has x for orginal and the other x+4 for the new square.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14358 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14358\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let original square have side \"x\".<BR>\n" );
document.write( "Its perimeter will be 4x.<BR>\n" );
document.write( "New square has side x+4 and has perimeter 4(x+4)=4x+16<BR>\n" );
document.write( "EQuATION:<BR>\n" );
document.write( "New perimeter =2(old perimeter)-8<BR>\n" );
document.write( "4x+16=2(4x)-8<BR>\n" );
document.write( "4x+16=8x-8<BR>\n" );
document.write( "4x=24<BR>\n" );
document.write( "x=6 (length of sideof the original square)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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