document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=191304>Question 191304</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectagular room is 104 square feet. The length of the room is 5 feet longer than the width. Find the dimensions of the room.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143576 by </B><A HREF=/tutors/aboutme.mpl?userid=kara%21><B>kara!(17)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kara%21><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143576\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  <BR>\n" );
document.write( " A= 104sq. feet<BR>\n" );
document.write( " Formula for the area of the rectangular room is: A=L*W( lenght times width)<BR>\n" );
document.write( "  because Lenght is 5 feet longer, it's going to be :L= W+5<BR>\n" );
document.write( "Let's put it in a formula<BR>\n" );
document.write( " (W+5)*W= 104<BR>\n" );
document.write( " W^2+5W-104=0<BR>\n" );
document.write( " after we solve this equation, we are going to find two answers, one is W=8<BR>\n" );
document.write( "the other W=-13( this can't be solution, because it's negative, and width  of the room can't be negative number)<BR>\n" );
document.write( " To find a Lenght, we will add 5 feet to the widht: L=8+5=13.<BR>\n" );
document.write( "So, the dimensions of the room are, 13ft and 8ft.<BR>\n" );
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