document.write( "Question 21675: very confused about these two questions\r
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document.write( "solve for x\r
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document.write( "x(x - 5) =4
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document.write( "and
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document.write( "(x +2))x-3)(x-6)=0\r
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document.write( "thanks for your help. \n" );
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Algebra.Com's Answer #14352 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1st: x^2-5x=4 \n" ); document.write( "x^2-5x-4=0 \n" ); document.write( "Use the quadratic formula to get: \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2nd: \n" ); document.write( "(x+2)(x-3)(x-6)=0 \n" ); document.write( "For this product to be zero one of these factors must be zero, so: \n" ); document.write( "x+2=0 or x-3=0 or x-6=0 \n" ); document.write( "So, x=-2 or x=3 or x=6\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |