document.write( "Question 21675: very confused about these two questions\r
\n" ); document.write( "\n" ); document.write( "solve for x\r
\n" ); document.write( "\n" ); document.write( "x(x - 5) =4
\n" ); document.write( "and
\n" ); document.write( "(x +2))x-3)(x-6)=0\r
\n" ); document.write( "\n" ); document.write( "thanks for your help.
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Algebra.Com's Answer #14352 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1st: x^2-5x=4
\n" ); document.write( "x^2-5x-4=0
\n" ); document.write( "Use the quadratic formula to get:
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-5x%2B-4+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-5%29%5E2-4%2A1%2A-4=41\".
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\n" ); document.write( " Discriminant d=41 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--5%2B-sqrt%28+41+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-5%29%2Bsqrt%28+41+%29%29%2F2%5C1+=+5.70156211871642\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-5%29-sqrt%28+41+%29%29%2F2%5C1+=+-0.701562118716424\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-5x%2B-4\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-5x%2B-4+=+1%28x-5.70156211871642%29%2A%28x--0.701562118716424%29\"
\n" ); document.write( " Again, the answer is: 5.70156211871642, -0.701562118716424.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-5%2Ax%2B-4+%29\"

\n" ); document.write( "\n" ); document.write( "2nd:
\n" ); document.write( "(x+2)(x-3)(x-6)=0
\n" ); document.write( "For this product to be zero one of these factors must be zero, so:
\n" ); document.write( "x+2=0 or x-3=0 or x-6=0
\n" ); document.write( "So, x=-2 or x=3 or x=6\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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