document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=191166>Question 191166</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one angle of two supplementary angles is four times the other angle. find the measure of the two angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143512 by </B><A HREF=/tutors/aboutme.mpl?userid=orca><B>orca(409)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=orca><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the smaller one be x, the the larger one is 4x.\r<BR>\n" );
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document.write( "As the sum of the two supplementary angles is 180 degrees, we have<BR>\n" );
document.write( "x + 4x = 180<BR>\n" );
document.write( "Solving for x, we have<BR>\n" );
document.write( "5x = 180<BR>\n" );
document.write( "x = 36<BR>\n" );
document.write( "So the two angles are:<BR>\n" );
document.write( "36 and 4x=4x36 = 144<BR>\n" );
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