document.write( "Question 191154: log2(x+1) - log2(x-1) = 4 \n" ); document.write( "

Algebra.Com's Answer #143503 by edjones(8007) $\"\"$ $\"About$

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log2(x+1) - log2(x-1) = 4
\n" ); document.write( "2^(log2(x+1)) / 2^( log2(x-1)) = 2^4
\n" ); document.write( "(x+1)/(x-1)=16
\n" ); document.write( "x+1=16(x-1)
\n" ); document.write( "x+1=16x-16
\n" ); document.write( "-15x=-17
\n" ); document.write( "x=17/15
\n" ); document.write( ".
\n" ); document.write( "Ed \n" ); document.write( "

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