document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26135>Question 26135</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Will someone please help me with this probelm. Im trying to solve for x: <BR>\n" );
document.write( "Log Base x of 8/27=-3.  Can someone help with the answer. And also please show me how to do it.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14350 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14350\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Take the anti-log to get x^(-3)=8/27<BR>\n" );
document.write( "Raise both sides to the -1/3 power to get:<BR>\n" );
document.write( "x=(8/27)^(-1/3)<BR>\n" );
document.write( "The negative in the exponent means to invert, so:<BR>\n" );
document.write( "x=(27/8)^(1/3)<BR>\n" );
document.write( "The 1/3 means to take the cube root, so:<BR>\n" );
document.write( "x=3/2<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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