document.write( "Question 191043: I started most of the work but I am not sure if I am doing it right. Please help.\r
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document.write( "Hypothesis Testing for Mean (Small Samples)\r
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document.write( "3. Metro Bank claims that the mean wait time for a teller during peak hours is less than 4 minutes. A random sample of 20 wait times has a mean of 2.6 minutes with a sample standard deviation of 2.1 minutes.
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document.write( "a. Use the critical value z0 method from the normal distribution to test for the population mean . Test the company’s claim at the level of significance = 0.05. \r
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document.write( "xbar = 2.6
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document.write( "µ = 4
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document.write( "s = 2.1
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document.write( "n = 20\r
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document.write( "d.f = n – 1 = 20 – 1 = 19
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document.write( "To find the critical value, use table 5 in Appendix B with d.f. = 19 and 0.05 in the “One Tail, ” column. Because the test is a left-tailed test, the critical value is negative. So
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document.write( "t0 = -1.729\r
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document.write( "1. H0 : u >= 4 minutes
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document.write( " Ha : u < 4 minutes
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document.write( "2. level of significance = 0.05
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document.write( "3. Test statistics: t = xbar - µ / s/√n (2.6-4)/[2.1/sqrt(20)] = -2.9814
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document.write( "4. P-value or critical z0 or t0.
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document.write( "5. Rejection Region: t < -1.729
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document.write( "6. Decision: Since -2.9814 is in the reject interval, Reject Ho.
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document.write( "7. Interpretation: The mean time is not <= 4 minutes \r
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document.write( "b. Use the critical value z0 method from the normal distribution to test for the population mean. Test the company’s claim at the level of significance = 0.01.\r
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document.write( "xbar = 2.6
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document.write( "µ = 4
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document.write( "s = 2.1
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document.write( "n = 20
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document.write( "d.f = n – 1 = 20 – 1 = 19
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document.write( "To find the critical value, use table 5 in Appendix B with d.f. = 19 and 0.01 in the “One Tail, level of significance ” column. Because the test is a left-tailed test, the critical value is negative. So
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document.write( "t0 = 2.539\r
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document.write( "1. H0 : u >= 4 minutes
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document.write( "2. Ha : u < 4 minutes
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document.write( "3. level of significance = 0.01
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document.write( "4. Test statistics:
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document.write( "5. P-value or critical z0 or t0.
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document.write( "6. Rejection Region:
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document.write( "7. Decision:
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document.write( "8. Interpretation: \r
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document.write( "Hypothesis Testing for Proportions.\r
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document.write( "4. In a recent poll, it was found that 43% of registered U.S. voters would vote for the incumbent president. If 100 registered voters were sampled randomly, it was found that 35% would vote of the incumbent. Test the claim that the actual proportion is 43%. \r
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document.write( "1. H0 :
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document.write( " Ha :
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document.write( "2. level of significance =
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document.write( "3. Test statistics:
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document.write( "4. P-value or critical z0 or t0.
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document.write( "5. Rejection Region:
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document.write( "6. Decision:
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document.write( "7. Interpretation:
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Algebra.Com's Answer #143486 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 3. Metro Bank claims that the mean wait time for a teller during peak hours is less than 4 minutes. A random sample of 20 wait times has a mean of 2.6 minutes with a sample standard deviation of 2.1 minutes. \r \n" ); document.write( "\n" ); document.write( "a. Use the critical value z0 method from the normal distribution to test for the population mean . Test the company’s claim at the level of significance = 0.05. \n" ); document.write( "xbar = 2.6 \n" ); document.write( "µ = 4 \n" ); document.write( "s = 2.1 \n" ); document.write( "n = 20 \n" ); document.write( "d.f = n – 1 = 20 – 1 = 19 \n" ); document.write( "To find the critical value, use table 5 in Appendix B with d.f. = 19 and 0.05 in the “One Tail, ” column. Because the test is a left-tailed test, the critical value is negative. So \n" ); document.write( "t0 = -1.729 \r \n" ); document.write( "\n" ); document.write( "1. H0 : u >= 4 minutes \n" ); document.write( "Ha : u < 4 minutes \n" ); document.write( "2. level of significance = 0.05 \n" ); document.write( "3. Test statistics: t = xbar - µ / s/√n (2.6-4)/[2.1/sqrt(20)] = -2.9814 \n" ); document.write( "4. P-value or critical z0 or t0. \n" ); document.write( "5. Rejection Region: t < -1.729 \n" ); document.write( "6. Decision: Since -2.9814 is in the reject interval, Reject Ho. \n" ); document.write( "7. Interpretation: The mean time is not <= 4 minutes \n" ); document.write( "--- \n" ); document.write( "part \"a\" looks good \n" ); document.write( "=================================================================\r \n" ); document.write( "\n" ); document.write( "b. Use the critical value z0 method from the normal distribution to test for the population mean. Test the company’s claim at the level of significance = 0.01. \n" ); document.write( "xbar = 2.6 \n" ); document.write( "µ = 4 \n" ); document.write( "s = 2.1 \n" ); document.write( "n = 20 \n" ); document.write( "d.f = n – 1 = 20 – 1 = 19 \n" ); document.write( "To find the critical value, use table 5 in Appendix B with d.f. = 19 and 0.01 in the “One Tail, level of significance ” column. Because the test is a left-tailed test, the critical value is negative. So \n" ); document.write( "t0 = 2.539 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1. H0 : u >= 4 minutes \n" ); document.write( "2. Ha : u < 4 minutes \n" ); document.write( "3. level of significance = 0.01 \n" ); document.write( "4. Test statistics: \n" ); document.write( "5. P-value or critical z0 or t0. \n" ); document.write( "6. Rejection Region: \n" ); document.write( "7. Decision: \n" ); document.write( "8. Interpretation: \n" ); document.write( "====================================================== \r \n" ); document.write( "\n" ); document.write( "Hypothesis Testing for Proportions. \n" ); document.write( "4. In a recent poll, it was found that 43% of registered U.S. voters would vote for the incumbent president. If 100 registered voters were sampled randomly, it was found that 35% would vote of the incumbent. Test the claim that the actual proportion is 43%. \n" ); document.write( "1. H0 : p = 0.43 \n" ); document.write( "Ha : p is not 0.43 \n" ); document.write( "-------------------------- \n" ); document.write( "2. level of significance = alpha = 5%, \n" ); document.write( "3. Test statistics: z(0.35) = (0.35-0.43)*sqrt[0.43*0.57/100] = -1.6159 \n" ); document.write( "4. P-value or critical z0 or t0.l: 2P(z<-1.6159) = 0.10611 \n" ); document.write( "5. Rejection Region: z<1.96 or z>1.96\r \n" ); document.write( "\n" ); document.write( "6. Decision: Since the p-value is greater than 5%, Fail to reject Ho. \n" ); document.write( "7. Interpretation: The test does not provide evidence that \n" ); document.write( "lead to rejecting the poll results. \n" ); document.write( "======================================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |