document.write( "Question 191043: I started most of the work but I am not sure if I am doing it right. Please help.\r
\n" ); document.write( "\n" ); document.write( "Hypothesis Testing for Mean (Small Samples)\r
\n" ); document.write( "\n" ); document.write( "3. Metro Bank claims that the mean wait time for a teller during peak hours is less than 4 minutes. A random sample of 20 wait times has a mean of 2.6 minutes with a sample standard deviation of 2.1 minutes.
\n" ); document.write( "
\n" ); document.write( "a. Use the critical value z0 method from the normal distribution to test for the population mean . Test the company’s claim at the level of significance  = 0.05. \r
\n" ); document.write( "\n" ); document.write( "xbar = 2.6
\n" ); document.write( "µ = 4
\n" ); document.write( "s = 2.1
\n" ); document.write( "n = 20\r
\n" ); document.write( "\n" ); document.write( "d.f = n – 1 = 20 – 1 = 19
\n" ); document.write( "To find the critical value, use table 5 in Appendix B with d.f. = 19 and 0.05 in the “One Tail, ” column. Because the test is a left-tailed test, the critical value is negative. So
\n" ); document.write( "t0 = -1.729\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1. H0 : u >= 4 minutes
\n" ); document.write( " Ha : u < 4 minutes
\n" ); document.write( "2. level of significance = 0.05
\n" ); document.write( "3. Test statistics: t = xbar - µ / s/√n (2.6-4)/[2.1/sqrt(20)] = -2.9814
\n" ); document.write( "4. P-value or critical z0 or t0.
\n" ); document.write( "5. Rejection Region: t < -1.729
\n" ); document.write( "6. Decision: Since -2.9814 is in the reject interval, Reject Ho.
\n" ); document.write( "7. Interpretation: The mean time is not <= 4 minutes \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "b. Use the critical value z0 method from the normal distribution to test for the population mean. Test the company’s claim at the level of significance  = 0.01.\r
\n" ); document.write( "\n" ); document.write( "xbar = 2.6
\n" ); document.write( "µ = 4
\n" ); document.write( "s = 2.1
\n" ); document.write( "n = 20
\n" ); document.write( "d.f = n – 1 = 20 – 1 = 19
\n" ); document.write( "To find the critical value, use table 5 in Appendix B with d.f. = 19 and 0.01 in the “One Tail, level of significance ” column. Because the test is a left-tailed test, the critical value is negative. So
\n" ); document.write( "t0 = 2.539\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1. H0 : u >= 4 minutes
\n" ); document.write( "2. Ha : u < 4 minutes
\n" ); document.write( "3. level of significance = 0.01
\n" ); document.write( "4. Test statistics:
\n" ); document.write( "5. P-value or critical z0 or t0.
\n" ); document.write( "6. Rejection Region:
\n" ); document.write( "7. Decision:
\n" ); document.write( "8. Interpretation: \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hypothesis Testing for Proportions.\r
\n" ); document.write( "\n" ); document.write( "4. In a recent poll, it was found that 43% of registered U.S. voters would vote for the incumbent president. If 100 registered voters were sampled randomly, it was found that 35% would vote of the incumbent. Test the claim that the actual proportion is 43%. \r
\n" ); document.write( "\n" ); document.write( "1. H0 :
\n" ); document.write( " Ha :
\n" ); document.write( "2. level of significance =
\n" ); document.write( "3. Test statistics:
\n" ); document.write( "4. P-value or critical z0 or t0.
\n" ); document.write( "5. Rejection Region:
\n" ); document.write( "
\n" ); document.write( "6. Decision:
\n" ); document.write( "7. Interpretation:
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #143486 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
3. Metro Bank claims that the mean wait time for a teller during peak hours is less than 4 minutes. A random sample of 20 wait times has a mean of 2.6 minutes with a sample standard deviation of 2.1 minutes. \r
\n" ); document.write( "\n" ); document.write( "a. Use the critical value z0 method from the normal distribution to test for the population mean . Test the company’s claim at the level of significance  = 0.05.
\n" ); document.write( "xbar = 2.6
\n" ); document.write( "µ = 4
\n" ); document.write( "s = 2.1
\n" ); document.write( "n = 20
\n" ); document.write( "d.f = n – 1 = 20 – 1 = 19
\n" ); document.write( "To find the critical value, use table 5 in Appendix B with d.f. = 19 and 0.05 in the “One Tail, ” column. Because the test is a left-tailed test, the critical value is negative. So
\n" ); document.write( "t0 = -1.729 \r
\n" ); document.write( "\n" ); document.write( "1. H0 : u >= 4 minutes
\n" ); document.write( "Ha : u < 4 minutes
\n" ); document.write( "2. level of significance = 0.05
\n" ); document.write( "3. Test statistics: t = xbar - µ / s/√n (2.6-4)/[2.1/sqrt(20)] = -2.9814
\n" ); document.write( "4. P-value or critical z0 or t0.
\n" ); document.write( "5. Rejection Region: t < -1.729
\n" ); document.write( "6. Decision: Since -2.9814 is in the reject interval, Reject Ho.
\n" ); document.write( "7. Interpretation: The mean time is not <= 4 minutes
\n" ); document.write( "---
\n" ); document.write( "part \"a\" looks good
\n" ); document.write( "=================================================================\r
\n" ); document.write( "\n" ); document.write( "b. Use the critical value z0 method from the normal distribution to test for the population mean. Test the company’s claim at the level of significance  = 0.01.
\n" ); document.write( "xbar = 2.6
\n" ); document.write( "µ = 4
\n" ); document.write( "s = 2.1
\n" ); document.write( "n = 20
\n" ); document.write( "d.f = n – 1 = 20 – 1 = 19
\n" ); document.write( "To find the critical value, use table 5 in Appendix B with d.f. = 19 and 0.01 in the “One Tail, level of significance ” column. Because the test is a left-tailed test, the critical value is negative. So
\n" ); document.write( "t0 = 2.539 \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1. H0 : u >= 4 minutes
\n" ); document.write( "2. Ha : u < 4 minutes
\n" ); document.write( "3. level of significance = 0.01
\n" ); document.write( "4. Test statistics:
\n" ); document.write( "5. P-value or critical z0 or t0.
\n" ); document.write( "6. Rejection Region:
\n" ); document.write( "7. Decision:
\n" ); document.write( "8. Interpretation:
\n" ); document.write( "====================================================== \r
\n" ); document.write( "\n" ); document.write( "Hypothesis Testing for Proportions.
\n" ); document.write( "4. In a recent poll, it was found that 43% of registered U.S. voters would vote for the incumbent president. If 100 registered voters were sampled randomly, it was found that 35% would vote of the incumbent. Test the claim that the actual proportion is 43%.
\n" ); document.write( "1. H0 : p = 0.43
\n" ); document.write( "Ha : p is not 0.43
\n" ); document.write( "--------------------------
\n" ); document.write( "2. level of significance = alpha = 5%,
\n" ); document.write( "3. Test statistics: z(0.35) = (0.35-0.43)*sqrt[0.43*0.57/100] = -1.6159
\n" ); document.write( "4. P-value or critical z0 or t0.l: 2P(z<-1.6159) = 0.10611
\n" ); document.write( "5. Rejection Region: z<1.96 or z>1.96\r
\n" ); document.write( "\n" ); document.write( "6. Decision: Since the p-value is greater than 5%, Fail to reject Ho.
\n" ); document.write( "7. Interpretation: The test does not provide evidence that
\n" ); document.write( "lead to rejecting the poll results.
\n" ); document.write( "=======================================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );