document.write( "Question 191085: Please help me solve this equation
\n" ); document.write( "5-5 Completing the Square\r
\n" ); document.write( "\n" ); document.write( " Solving a quadratic equation if the coefficient of x^2 is NOT 1\r
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\n" ); document.write( "\n" ); document.write( " 3x^2+12x-9=0
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Algebra.Com's Answer #143442 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First, let's complete the square for the left side of the equation \"3x%5E2%2B12x-9=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2%2B12x-9\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%5E2%2B4x-3%29\" Factor out the \"x%5E2\" coefficient \"3\". This step is very important: the \"x%5E2\" coefficient must be equal to 1.\r
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\n" ); document.write( "\n" ); document.write( "Take half of the \"x\" coefficient \"4\" to get \"2\". In other words, \"%281%2F2%29%284%29=2\".\r
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\n" ); document.write( "\n" ); document.write( "Now square \"2\" to get \"4\". In other words, \"%282%29%5E2=%282%29%282%29=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%5E2%2B4x%2Bhighlight%284-4%29-3%29\" Now add and subtract \"4\" inside the parenthesis. Make sure to place this after the \"x\" term. Notice how \"4-4=0\". So the expression is not changed.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28%28x%5E2%2B4x%2B4%29-4-3%29\" Group the first three terms.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28%28x%2B2%29%5E2-4-3%29\" Factor \"x%5E2%2B4x%2B4\" to get \"%28x%2B2%29%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"3%28%28x%2B2%29%5E2-7%29\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%2B2%29%5E2%2B3%28-7%29\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%2B2%29%5E2-21\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "So after completing the square, \"3x%5E2%2B12x-9\" transforms to \"3%28x%2B2%29%5E2-21\". So \"3x%5E2%2B12x-9=3%28x%2B2%29%5E2-21\".\r
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\n" ); document.write( "\n" ); document.write( "So \"3x%5E2%2B12x-9=0\" is equivalent to \"3%28x%2B2%29%5E2-21=0\".\r
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\n" ); document.write( "\n" ); document.write( "Now let's solve \"3%28x%2B2%29%5E2-21=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%2B2%29%5E2-21=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%2B2%29%5E2=21\" Add 21 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%5E2=%2821%29%2F%283%29\" Divide both sides by \"3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%5E2=7\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B2=%22%22%2B-sqrt%287%29\" Take the square root of both sides. (note: don't forget the \"plus/minus\")\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B2=sqrt%287%29\" or \"x%2B2=-sqrt%287%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"x=-2%2Bsqrt%287%29\" or \"x=-2-sqrt%287%29\" Subtract \"2\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=-2%2Bsqrt%287%29\" or \"x=-2-sqrt%287%29\".
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