document.write( "Question 191062: if the exterior angles of a convex polygon are x/13, 2x-1, 2x/6,2x+12,2x-17,3x-4,3x-10 and 4x calculate the smallest of eight angles. \n" ); document.write( "
Algebra.Com's Answer #143429 by solver91311(24713) You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sum of the exterior angles of a polygon, regular or otherwise, and regardless of the number of sides, is 180°.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So solve: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hint: Multiply by 13 and then by 6 to get rid of the denominators. You will have large coefficients to deal with, but I think that is less messy than fractions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Once you have done that, substitute your value for x into each of the given expressions and see which is the smallest. Just guessing, but I suspect that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |