document.write( "Question 191036This question is from textbook algebra and trigonometry structure and method book 2
\n" ); document.write( ": In problems 11 and 12, use the fact that the load a beam with a rectangular cross section can support is jointly proportional to the beams width and the square of its depth and inversely proportional to it's length.
\n" ); document.write( "11. A beam 2 cm wide and 5cm deep can support a load of 630kg. What load can it support when turned on its side?
\n" ); document.write( "please please please explain what you are doing if you answer this problem. it is so confusing i cant even think of what to do.
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Algebra.Com's Answer #143416 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
In problems 11 and 12, use the fact that the load a beam with a rectangular cross section can support is jointly proportional to the beams width and the square of its depth and inversely proportional to it's length.
\n" ); document.write( "load = k[wd^2/L]
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\n" ); document.write( "11. A beam 2 cm wide and 5cm deep can support a load of 630kg. What load can it support when turned on its side?
\n" ); document.write( "1st You need to solve for \"k\"
\n" ); document.write( "630 = k[2*5^2/L]
\n" ); document.write( "630 = k[50/L]
\n" ); document.write( "k = 630L/50
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\n" ); document.write( "Now you know the equation for this beam is load = [630L/50][wd^2/L]
\n" ); document.write( "load = 630wd^2/50
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\n" ); document.write( "Now if you turn the beam on its side w = 5 and depth = 2, so you get:
\n" ); document.write( "load = 630*5*2^2/50
\n" ); document.write( "load = 630*20/50
\n" ); document.write( "load = 630(2/5)
\n" ); document.write( "load = 126*2 = 252 kg
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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\n" ); document.write( "\n" ); document.write( "please please please explain what you are doing if you answer this problem. it is so confusing i cant even think of what to do.
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