document.write( "Question 190998: Zoha jogs 3 miles per hour faster than she walks. She jogs for 2 miles and then walks for 2 miles. If the total time of her outing is one hour, find the rate at which she walks and jogs? \n" ); document.write( "
Algebra.Com's Answer #143410 by ankor@dixie-net.com(22740)\"\" \"About 
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Zoha jogs 3 miles per hour faster than she walks. She jogs for 2 miles and then
\n" ); document.write( "walks for 2 miles. If the total time of her outing is one hour, find the rate at
\n" ); document.write( " which she walks and jogs?
\n" ); document.write( ":
\n" ); document.write( "Let x = walking speed
\n" ); document.write( "then
\n" ); document.write( "(x+3) = jogging speed
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; Time = \"dist%2Fspeed\"
\n" ); document.write( ":
\n" ); document.write( "walk time + jog time = 1 hr
\n" ); document.write( "\"2%2Fx\" + \"2%2F%28%28x%2B3%29%29\" = 1
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by x(x+3), results:
\n" ); document.write( "2(x+3) + 2x = x(x+3)
\n" ); document.write( "2x + 6 + 2x = x^2 + 3x
\n" ); document.write( "4x + 6 = x^2 + 3x
\n" ); document.write( "0 = x^2 + 3x - 4x - 6
\n" ); document.write( "a quadratic equation:
\n" ); document.write( "x^2 - x - 6 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x-3)(x+2) = 0
\n" ); document.write( "Positive solution
\n" ); document.write( "x = 3 mph is the walking speed
\n" ); document.write( "then
\n" ); document.write( "3 + 3 = 6 mph is the jogging speed
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution:
\n" ); document.write( "2/3 + 2/6 = 1
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