document.write( "Question 190998: Zoha jogs 3 miles per hour faster than she walks. She jogs for 2 miles and then walks for 2 miles. If the total time of her outing is one hour, find the rate at which she walks and jogs? \n" ); document.write( "
Algebra.Com's Answer #143410 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Zoha jogs 3 miles per hour faster than she walks. She jogs for 2 miles and then \n" ); document.write( "walks for 2 miles. If the total time of her outing is one hour, find the rate at \n" ); document.write( " which she walks and jogs? \n" ); document.write( ": \n" ); document.write( "Let x = walking speed \n" ); document.write( "then \n" ); document.write( "(x+3) = jogging speed \n" ); document.write( ": \n" ); document.write( "Write a time equation; Time = \n" ); document.write( ": \n" ); document.write( "walk time + jog time = 1 hr \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by x(x+3), results: \n" ); document.write( "2(x+3) + 2x = x(x+3) \n" ); document.write( "2x + 6 + 2x = x^2 + 3x \n" ); document.write( "4x + 6 = x^2 + 3x \n" ); document.write( "0 = x^2 + 3x - 4x - 6 \n" ); document.write( "a quadratic equation: \n" ); document.write( "x^2 - x - 6 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(x-3)(x+2) = 0 \n" ); document.write( "Positive solution \n" ); document.write( "x = 3 mph is the walking speed \n" ); document.write( "then \n" ); document.write( "3 + 3 = 6 mph is the jogging speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution: \n" ); document.write( "2/3 + 2/6 = 1 \n" ); document.write( " \n" ); document.write( " |