document.write( "Question 190997: Zoha jogs 3 miles per hour faster than she walks. She jogs for 2 miles and then walks for 2 miles. If the total time of her outing is one hour, find the rate at which she walks and jogs? \n" ); document.write( "

Algebra.Com's Answer #143406 by orca(409) $\"\"$ $\"About$

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Let x represent the speed at which she walks, then the speed at which she jogs is x +3.
\n" ); document.write( "The time spent on joging is $\"2%2F%28x%2B2%29\"$
\n" ); document.write( "The time spent on walking is $\"2%2Fx\"$ .
\n" ); document.write( "The total time spent is $\"2%2F%28x%2B2%29%2B2%2Fx\"$
\n" ); document.write( "We have already been given the total time spent: one hour.\r
\n" ); document.write( "\n" ); document.write( "So $\"2%2F%28x%2B3%29%2B2%2Fx+=+1\"$ \r
\n" ); document.write( "\n" ); document.write( "Solving for x, we have
\n" ); document.write( " $\"2x+%2B+2%28x%2B3%29+=+x%28x%2B3%29\"$ multiply both sides by x(x+3)
\n" ); document.write( " $\"2x+%2B+2x+%2B+6+=+x%5E2+%2B+3x\"$
\n" ); document.write( " $\"4x+%2B+6+=+x%5E2+%2B+3x\"$
\n" ); document.write( " $\"0+=+x%5E2+-x+-6\"$
\n" ); document.write( " $\"x%5E2+-x+-6+=+0\"$
\n" ); document.write( " $\"%28x-3%29%28x%2B2%29=+0\"$
\n" ); document.write( "So
\n" ); document.write( "x=3
\n" ); document.write( "or
\n" ); document.write( "x=-2(reject this negative solution)\r
\n" ); document.write( "\n" ); document.write( "So her walking speed is 3 miles/hour, her joging speed is x + 3 = 6 miles/hour.
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