document.write( "Question 26479: Solve each system of equations using the substitution method.
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document.write( "1)4x+y=160
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document.write( "12x-13y=-160 \r
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Algebra.Com's Answer #14339 by algebrawiz(2)![]() ![]() ![]() You can put this solution on YOUR website! Ok, lets go through the steps. \n" ); document.write( "1.You need to solve the equation for x or y. Using the first equation(4x+y=16) lets solve for y. \n" ); document.write( " \n" ); document.write( " a. 4x + y = 16 \n" ); document.write( " b. subtract 4x from both sides \n" ); document.write( " c. we get y =-4x + 16 \n" ); document.write( "2.Now we can use this information to solve the problem by substituting -4x+16 into y for the second equation (12x-13y=-160). Lets do this:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " a. 12x - 13y = -160 \n" ); document.write( " b. 12x - 13(-4x+16) = -160 plug -4x+16 in for y \n" ); document.write( " c 12x - (-52x+208) = -160 distribute the 13 (notice I put the answer in parentheses so that I can distribute the - sign.) \n" ); document.write( " \n" ); document.write( " d. 12x + 52x - 208 = -160 distibute the - sign \n" ); document.write( " e. 64x - 208 = -160 combine like terms (x), now solve for x \n" ); document.write( " f. add 208 to both sides \n" ); document.write( " g. 64x = 48 next divide both sides by 64 \n" ); document.write( " \n" ); document.write( " h. x= 48/64 = .75 since we know y=-4x+16 lets plug in x to find y \n" ); document.write( " i.y= -4(.75)+16 do the math \n" ); document.write( " y=13 so the answer is x=.75 and y= 13\r \n" ); document.write( "\n" ); document.write( "The best part of algebra is that you can check the solution by pluging it back into the problem. Remember it must be true for both of the ORIGINAL equation \n" ); document.write( " |