document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=190977>Question 190977</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, was wondering if anyone could help me with the following system of equations problem. Steps on how to solve fully would be ideal also.\r<BR>\n" );
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document.write( "A-B+C=1<BR>\n" );
document.write( "2A-2B=0<BR>\n" );
document.write( "3A+B-3C=2\r<BR>\n" );
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document.write( "Any help would be most appreciated, <BR>\n" );
document.write( "-Thanks, -Nick. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143387 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143387\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A  -B  + C = 1<BR>\n" );
document.write( "2A -2B + 0 = 0<BR>\n" );
document.write( "3A +B  -3C = 2 <BR>\n" );
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document.write( "Subtract 2 times the 1st from the 2nd; Subtract 3 times the 1st from the 3rd:<BR>\n" );
document.write( "A  -B  + C = 1<BR>\n" );
document.write( "0  +0  -2C = -2<BR>\n" );
document.write( "0  +4B -6C = -1 <BR>\n" );
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document.write( "The 2nd equation tells us that C = 1<BR>\n" );
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document.write( "Substitute that into the 3rd equation to solve for \"B\":<BR>\n" );
document.write( "4B - 6 = -1<BR>\n" );
document.write( "4B = 5<BR>\n" );
document.write( "B = 5/4<BR>\n" );
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document.write( "Substitute those values into the 1st equation to solve for \"A\":<BR>\n" );
document.write( "A - (5/4) + 1 = 1<BR>\n" );
document.write( "A = 5/4<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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