document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=190977>Question 190977</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, was wondering if anyone could help me with the following system of equations problem. Steps on how to solve fully would be ideal also.\r<BR>\n" );
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document.write( "A-B+C=1<BR>\n" );
document.write( "2A-2B=0<BR>\n" );
document.write( "3A+B-3C=2\r<BR>\n" );
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document.write( "Any help would be most appreciated, <BR>\n" );
document.write( "-Thanks, -Nick. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143384 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143384\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A - B + C = 1<BR>\n" );
document.write( "2A -2B = 0<BR>\n" );
document.write( "3A + B -3C = 2<BR>\n" );
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document.write( "multiply the 1st equation by 2, subtract the 2nd equation<BR>\n" );
document.write( "2A - 2B + 2C = 2<BR>\n" );
document.write( "2A - 2B + 0C = 0<BR>\n" );
document.write( "------------------ subtraction eliminates A & B, find C<BR>\n" );
document.write( "2C = 2<BR>\n" );
document.write( "C = 1<BR>\n" );
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document.write( "Substitute 1 for C in the 1st and 3rd equations<BR>\n" );
document.write( "A - B + 1 = 1<BR>\n" );
document.write( "3A +B -3(1) = 2<BR>\n" );
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document.write( "A - B = 1 - 1<BR>\n" );
document.write( "3A +B = 2 + 3<BR>\n" );
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document.write( "A - B = 0<BR>\n" );
document.write( "3A +B = 5<BR>\n" );
document.write( "------------Adding eliminates B<BR>\n" );
document.write( "4A = 5<BR>\n" );
document.write( "A = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F4 ALIGN=MIDDLE  ALT=\"5%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Find B using 2A - 2B = 0; therefore: B = A<BR>\n" );
document.write( "B = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F4 ALIGN=MIDDLE  ALT=\"5%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Solution: A = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F4 ALIGN=MIDDLE  ALT=\"5%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >, B = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F4 ALIGN=MIDDLE  ALT=\"5%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >, C = 1<BR>\n" );
document.write( ";<BR>\n" );
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document.write( "Check solution in the 3rd equation:<BR>\n" );
document.write( "3A + B -3C = 2<BR>\n" );
document.write( "3(<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F4 ALIGN=MIDDLE  ALT=\"5%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >) + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F4 ALIGN=MIDDLE  ALT=\"5%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > - 3(1) = 2<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15%2F4 ALIGN=MIDDLE  ALT=\"15%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F4 ALIGN=MIDDLE  ALT=\"5%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > - 3 = 2<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=20%2F4 ALIGN=MIDDLE  ALT=\"20%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > - 3 = 2<BR>\n" );
document.write( "5 - 3 = 2 </SPAN>\n" );
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