document.write( "Question 190939: Please help me with this question 3n(squared) + 2n - 1. Thank You \n" ); document.write( "
Algebra.Com's Answer #143354 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming you want to factor?\r
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"3n%5E2%2B2n-1\", we can see that the first coefficient is \"3\", the second coefficient is \"2\", and the last term is \"-1\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"3\" by the last term \"-1\" to get \"%283%29%28-1%29=-3\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-3\" (the previous product) and add to the second coefficient \"2\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-3\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-3\":\r
\n" ); document.write( "\n" ); document.write( "1,3\r
\n" ); document.write( "\n" ); document.write( "-1,-3\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-3\".\r
\n" ); document.write( "\n" ); document.write( "1*(-3)
\n" ); document.write( "(-1)*(3)\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"2\":\r
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First NumberSecond NumberSum
1-31+(-3)=-2
-13-1+3=2
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"-1\" and \"3\" add to \"2\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"-1\" and \"3\" both multiply to \"-3\" and add to \"2\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"2n\" with \"-n%2B3n\". Remember, \"-1\" and \"3\" add to \"2\". So this shows us that \"-n%2B3n=2n\".\r
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\n" ); document.write( "\n" ); document.write( "\"3n%5E2%2Bhighlight%28-n%2B3n%29-1\" Replace the second term \"2n\" with \"-n%2B3n\".\r
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\n" ); document.write( "\n" ); document.write( "\"%283n%5E2-n%29%2B%283n-1%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"n%283n-1%29%2B%283n-1%29\" Factor out the GCF \"n\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"n%283n-1%29%2B1%283n-1%29\" Factor out \"1\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28n%2B1%29%283n-1%29\" Combine like terms. Or factor out the common term \"3n-1\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"3n%5E2%2B2n-1\" factors to \"%28n%2B1%29%283n-1%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by FOILing \"%28n%2B1%29%283n-1%29\" to get \"3n%5E2%2B2n-1\" or by graphing the original expression and the answer (the two graphs should be identical).
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