document.write( "Question 190905: Hello. I am not positive I put in the right topic. We are learning complex algebraic fractions. I solved a problem, and I am not sure if i solved it correctly, and if I did I am not sure how to show the work for the check. the problem is x-1/x + 7/3x = 9/4x
\n" ); document.write( "we have to cancel the denominators by finding an LCD and multiplying by that.
\n" ); document.write( "EX: LCD for the above problem is 12x, so i would x x-1 x 12x and the x and 12 x simplify it to 12x-12. \r
\n" ); document.write( "\n" ); document.write( "The answer i got is 11/12, but I am not sure if it is correct.
\n" ); document.write( "If not, please provide help on solving it because I am quite confused, and if you don't mind please assist me in the check (if the correct solution is a fraction because my teacher goes too fast and never stops so I am not able to ask for help) \r
\n" ); document.write( "\n" ); document.write( "thank you so much for your help :)\r
\n" ); document.write( "\n" ); document.write( "~Katie
\n" ); document.write( "

Algebra.Com's Answer #143350 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
the problem is \"%28%28x-1%29%29%2Fx\" + \"7%2F%283x%29\" = \"9%2F%284x%29\"
\n" ); document.write( "I think you are right but let's just go thru it and check the solution
\n" ); document.write( "12x*\"%28%28x-1%29%29%2Fx\" + 12x*\"7%2F%283x%29\" = 12x*\"9%2F%284x%29\"
\n" ); document.write( "Cancel out the denominators and you have:
\n" ); document.write( "12(x-1) + 4(7) = 3(9)
\n" ); document.write( "12x - 12 + 28 = 27
\n" ); document.write( "12x + 16 = 27
\n" ); document.write( "12x = 27 - 16
\n" ); document.write( "12x = 11
\n" ); document.write( "x = \"11%2F12\" just as you said
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "But you can be sure by substituting 11/12 for x in the original problem:
\n" ); document.write( "\"%28%28x-1%29%29%2Fx\" + \"7%2F%283x%29\" = \"9%2F%284x%29\"
\n" ); document.write( "Remember when you have a fraction in the denominator, you invert it and mult
\n" ); document.write( "the numerator:
\n" ); document.write( "((11/12) - 1)*(12/11)) + 7(12/33) = 9(12/44)
\n" ); document.write( ":
\n" ); document.write( "((-1/12)*(12/11)) + 7(12/33) = 9(12/44)
\n" ); document.write( ";
\n" ); document.write( "(-1/11) + (84/33) = (108/44)
\n" ); document.write( ";
\n" ); document.write( "Reduce the fractions
\n" ); document.write( "(-1/11) + (28/11) = (27/11); confirms our solution
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