document.write( "Question 190916This question is from textbook saxon algebra 2
\n" );
document.write( ": Graph, find center, vertices, co-vertices and foci.
\n" );
document.write( "9x^2+4y=36
\n" );
document.write( "I worked it out to:
\n" );
document.write( "center(0,0)
\n" );
document.write( "a=3 b=2 c=5
\n" );
document.write( "vertices(0,+-3)
\n" );
document.write( "co-vertices(+-2,0)
\n" );
document.write( "foci(0,+-5)
\n" );
document.write( "eccentricity=5/3
\n" );
document.write( "Did I do this right? When I graph it, the foci is outside the circle. Is that right? \n" );
document.write( "
Algebra.Com's Answer #143341 by stanbon(75887) ![]() You can put this solution on YOUR website! Graph, find center, vertices, co-vertices and foci. \n" ); document.write( "9x^2+4y=36 \n" ); document.write( "y = (-9/4)x^2 + 9 \n" ); document.write( "--------- \n" ); document.write( "It's not a circle ; it's a parabola \n" ); document.write( "There is no center and no co-vertices. \n" ); document.write( "--------- \n" ); document.write( "Vertex form by squaring the x-terms:\r \n" ); document.write( "\n" ); document.write( "9(x-0)^2 = -4(y-9) \n" ); document.write( "(x-0)^2 = (-4/9)(y-9) \n" ); document.write( "h = 0; k = 9 \n" ); document.write( "4p = -4/9 \n" ); document.write( "p = -1/9 \n" ); document.write( "--------------------------- \n" ); document.write( "Vertex: (0 , 9) \n" ); document.write( "Focus (0 , 80/9) \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |