document.write( "Question 190916This question is from textbook saxon algebra 2
\n" ); document.write( ": Graph, find center, vertices, co-vertices and foci.
\n" ); document.write( "9x^2+4y=36
\n" ); document.write( "I worked it out to:
\n" ); document.write( "center(0,0)
\n" ); document.write( "a=3 b=2 c=5
\n" ); document.write( "vertices(0,+-3)
\n" ); document.write( "co-vertices(+-2,0)
\n" ); document.write( "foci(0,+-5)
\n" ); document.write( "eccentricity=5/3
\n" ); document.write( "Did I do this right? When I graph it, the foci is outside the circle. Is that right?
\n" ); document.write( "

Algebra.Com's Answer #143341 by stanbon(75887)\"\" \"About 
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Graph, find center, vertices, co-vertices and foci.
\n" ); document.write( "9x^2+4y=36
\n" ); document.write( "y = (-9/4)x^2 + 9
\n" ); document.write( "---------
\n" ); document.write( "It's not a circle ; it's a parabola
\n" ); document.write( "There is no center and no co-vertices.
\n" ); document.write( "---------
\n" ); document.write( "Vertex form by squaring the x-terms:\r
\n" ); document.write( "\n" ); document.write( "9(x-0)^2 = -4(y-9)
\n" ); document.write( "(x-0)^2 = (-4/9)(y-9)
\n" ); document.write( "h = 0; k = 9
\n" ); document.write( "4p = -4/9
\n" ); document.write( "p = -1/9
\n" ); document.write( "---------------------------
\n" ); document.write( "Vertex: (0 , 9)
\n" ); document.write( "Focus (0 , 80/9)
\n" ); document.write( "======================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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