document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=190888>Question 190888</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780395977255/algebrahomeworkh>algebra and trigonometry structure and method book 2</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\">  In problems 11 and 12, use the fact that the load a beam with a rectangular cross section can support is jointly proportional to the beams width and the square of its depth and inversely proportional to it's length. <BR>\n" );
document.write( "11. A beam 3 cm wide and 5cm deep can support a load of 630kg. What load can it support when turned on its side?\r<BR>\n" );
document.write( "\n" );
document.write( "please please please explain what you are doing if you answer this problem. it is so confusing i cant even think of what to do.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143329 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143329\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
document.write( "\n" );
document.write( "If the load weight is jointly proportional to the width and the square of the depth and inversely proportional to the beam length, then you can write the relationship thus:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ L = \frac{kwd^2}{l}\">\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Where  <i><b>L</b></i> is the load weight, <i><b>w</b></i> is the beam width, <i><b>d</b></i> is the beam depth, <i><b>l</b></i> is the beam length, and <i><b>k</b></i> is the constant of proportionality.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "If something is proportional it goes in the numerator -- it is proportional to <i><b>w</b></i> and <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE d^2\">, so both go in the numerator.  If it is inversely proportional, it goes in the denominator, like our <i><b>l</b></i>.  And finally, you have to put in a constant of proportionality.  It doesn't matter where that goes except that it is generally computationally easier if you leave it in the numerator.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Since you didn't give the beam length, what we need to do is to calculate a value for <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \frac{k}{l}\"> given that <i><b>w</b></i> = 3 cm, <i><b>d</b></i> = 5 cm, and <i><b>L</b></i> = 630 kg.  So substitute the values:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ 630 = \frac{k(3)(5)^2}{l} = \frac{75k}{l}\">\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "And then:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \frac{k}{l} = \frac{630}{75} = 8.4\">\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Now re-write your proportion:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ L = 8.4\,\cdot\,wd^2\">\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "And substitute the new values for <i><b>w</b></i> and <i><b>d</b></i>, namely 5 and 3 respectively.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ L = 8.4\,\cdot\,(5)(3)^2 = 8.4\,\cdot\,45 = 378\text{ kg}\">\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "</font> </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );