document.write( "Question 190827This question is from textbook algebra and trigonometry structure and method book 2
\n" ); document.write( ": In problems 11 and 12, use the fact that the load a beam with a rectangular cross section can support is jointly proportional to the beams width and the square of its depth and inversely proportional to it's length.\r
\n" ); document.write( "\n" ); document.write( "11. A beam 2 cm wide and 5cm deep can support a load of 630kg. What load can it support when turned on its side?
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Algebra.Com's Answer #143300 by Mathtut(3670)\"\" \"About 
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lets call the support s length L width w and depth d
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\n" ); document.write( "sL/wd=k
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\n" ); document.write( "\"630L%2F2%285%29%5E2=k\"
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\n" ); document.write( "\"k=630L%2F50\"
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\n" ); document.write( "now the width is 5 and the depth is 2 find s
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\n" ); document.write( "\"sL%2F5%282%29%5E2=630L%2F50\"
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\n" ); document.write( "\"s=630%2A20%2F50=252\"kg ..........L's cancelled each other
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