document.write( "Question 190776: Can someone please help me with this problem:\r
\n" ); document.write( "\n" ); document.write( "The speed of a 4000-kg truch whose KE is 1.8 MJ is:\r
\n" ); document.write( "\n" ); document.write( "a. 0.95 m/s
\n" ); document.write( "b. 30 m/s
\n" ); document.write( "c. 94 m/s
\n" ); document.write( "d. 900 m/s
\n" ); document.write( "

Algebra.Com's Answer #143262 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming that you've been given the kinetic energy formula: \"KE=%281%2F2%29mv%5E2\" where \"KE\" is the kinetic energy (think of it as the energy it has when it is moving), \"m\" is the mass, and \"v\" is the velocity\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Note: the units for the three variables are:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "KE: joules (j)\r
\n" ); document.write( "\n" ); document.write( "m: kilograms (kg)\r
\n" ); document.write( "\n" ); document.write( "v: meters per second (m/s)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the units in this problem are very important\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "First, take note that 4000 kg in scientific notation is written as \"m=4%2A10%5E3\" kilograms\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Also, 1.8 MJ (1.8 megajoules) can be written as 1,800,000 joules, which is \"1.8%2A10%5E6\" joules. So the kinetic energy is \"KE=1.8%2A10%5E6\" joules.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"KE=%281%2F2%29mv%5E2\" Start with the given formula\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1.8%2A10%5E6=%281%2F2%29%284%2A10%5E3%29v%5E2\" Plug in \"KE=1.8%2A10%5E6\" and \"m=4%2A10%5E3\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1.8%2A10%5E6=%282%2A10%5E3%29v%5E2\" Multiply \"1%2F2\" by \"4%2A10%5E3\" to get \"2%2A10%5E3\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%281.8%2A10%5E6%29%2F%282%2A10%5E3%29=v%5E2\" Divide both sides by \"2%2A10%5E3\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"900=v%5E2\" Divide\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"v%5E2=900\" Rearrange the equation\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"v=sqrt%28900%29\" Take the square root of both sides (we're only interested in the positive square root)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"v=30\" Take the square root of 900 to get 30\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the velocity is 30 m/s
\n" ); document.write( "
\n" );