document.write( "Question 190741: This question is from a homework that was handed out in class.
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document.write( "I don't understand the problem, please help me.
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document.write( "Thanks\r
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document.write( "Solve for x
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document.write( "(x+4)^1/2 + 5x(x+4)^3/2 =0\r
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Algebra.Com's Answer #143213 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! (x+4)^1/2 + 5x(x+4)^3/2 =0 \n" ); document.write( ". \n" ); document.write( "Begin by factoring out (x+4)^1/2: \n" ); document.write( "(x+4)^1/2 [1 + 5x(x+4)^2/2] = 0 \n" ); document.write( "(x+4)^1/2 [1 + 5x(x+4)] = 0 \n" ); document.write( "(x+4)^1/2 [1 + 5x^2 + 20x] = 0 \n" ); document.write( "(x+4)^1/2 [5x^2 + 20x + 1] = 0 \n" ); document.write( ". \n" ); document.write( "Now, the problem is reduced to finding values of 'x' when: \n" ); document.write( "(x+4)^1/2 = 0 \n" ); document.write( "and \n" ); document.write( "5x^2 + 20x + 1 = 0 \n" ); document.write( ". \n" ); document.write( "Top one: \n" ); document.write( "(x+4)^1/2 = 0 \n" ); document.write( "(x+4) = 0 \n" ); document.write( "x = -4 \n" ); document.write( ". \n" ); document.write( "Bottom one: \n" ); document.write( "5x^2 + 20x + 1 = 0 \n" ); document.write( "Applying the quadratic equation yields two solutions: \n" ); document.write( "x = {-0.051, -3.949} \n" ); document.write( ". \n" ); document.write( "Combined solutions, then are: \n" ); document.write( "x = {-0.051, -3.949, -4} \n" ); document.write( ". \n" ); document.write( "Details of the quadratic follows: \n" ); document.write( "
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