Algebra.Com's Answer #1432 by drglass(89)![\"\"](\"/images/stars/stars-08.gif\")  
You can put this solution on YOUR website!
To find factors of a number N it is enough to search the odd numbers from 3- . The table below whether or not a number is a factor of 499 by checking whether or not 499/n has a remainder (you will need to scroll down to see the table).
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document.write( "| n | remainder | \r\n" );
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document.write( "| 3 | yes | \r\n" );
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document.write( "| 7 | yes | \r\n" );
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document.write( "| 13 | yes | \r\n" );
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document.write( "| 17 | yes | \r\n" );
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document.write( "| 19 | yes | \r\n" );
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document.write( "| 21 | yes | \r\n" );
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document.write( "Since 499 has no factors, it must be prime. I skipped some possible values like 5 and 9. Do you know why? \n" );
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