Algebra.Com's Answer #143171 by Alan3354(69443)  You can put this solution on YOUR website! 5x^4 + 14x^2 - 3 = 0 \n" );
document.write( "This is a quadratic in x^2. Use the quadratic equation to find 2 zeroes for x^2, then get the sqrt of those. \n" );
document.write( "(5x^2 - 1)*(x^2 + 3) = 0\r \n" );
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document.write( "x^2 = 1/5 \n" );
document.write( "x = +sqrt(5)/5 \n" );
document.write( "x = -sqrt(5)/5 \n" );
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document.write( "x^2 = -3 \n" );
document.write( "x = +3i \n" );
document.write( "x = -3i \n" );
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document.write( "x^2 + 3 = 0 \n" );
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document.write( " Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) | \n" );
document.write( "Quadratic equation (in our case ) has the following solutons: \n" );
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document.write( " For these solutions to exist, the discriminant should not be a negative number. \n" );
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document.write( " First, we need to compute the discriminant : . \n" );
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document.write( " The discriminant -12 is less than zero. That means that there are no solutions among real numbers.
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document.write( " If you are a student of advanced school algebra and are aware about imaginary numbers, read on.
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document.write( " In the field of imaginary numbers, the square root of -12 is + or - . \n" );
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document.write( " The solution is , or \n" );
document.write( " Here's your graph: \n" );
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