document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26422>Question 26422</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i need help in solving with a coin and intrest problem> it goes like this an invester has 500$ more invested at 7% than he does at 5%. if his annual interest is $515, how much does he have invested at each rate?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14313 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14313\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let amount invested at 5% be \"x\".<BR>\n" );
document.write( "The amount invested at 7% is \"x+500\"<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "Interest + Interest= $515<BR>\n" );
document.write( "0.05x + 0.07(x+500)=515<BR>\n" );
document.write( "Multiply through be 100 to get:<BR>\n" );
document.write( "5x+7x+3500=51500<BR>\n" );
document.write( "12x=48000<BR>\n" );
document.write( "x=4000 (amount invested at 5%<BR>\n" );
document.write( "x+500=4500 (amount invested at 7%)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );