document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26422>Question 26422</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i need help in solving with a coin and intrest problem> it goes like this an invester has 500$ more invested at 7% than he does at 5%. if his annual interest is $515, how much does he have invested at each rate?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14312 by </B><A HREF=/tutors/aboutme.mpl?userid=wuwei96815><B>wuwei96815(245)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wuwei96815><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14312\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If we let x = amount invested at 5% and x+500 = the amount invested at 7%, we can write and solve the following equation:<BR>\n" );
document.write( "5%x + 7%(x+500) = $515.\r<BR>\n" );
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document.write( "5%x + 7%(x+500) = $515<BR>\n" );
document.write( "0.05x + 0.07x + 35 = 515<BR>\n" );
document.write( "0.12x = 515 - 35 = 480<BR>\n" );
document.write( "x = 480/0.12 = 4000\r<BR>\n" );
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document.write( "x = $4000<BR>\n" );
document.write( "x+500 = $4500  </SPAN>\n" );
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