document.write( "Question 190631: A group of students decides to sell pizzas to help raise money. They sold pepperoni for $12, sausage for $10, and cheese for $8. The class sold a total of 600 pizzas and made $5900. The students sold 175 more cheese pizzas than sausage. Set up a system of three equations and three unkowns, use the augemented matrix to solve. \n" ); document.write( "
Algebra.Com's Answer #143113 by jim_thompson5910(35256)\"\" \"About 
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Let \r
\n" ); document.write( "\n" ); document.write( "x = # of pepperoni pizzas sold\r
\n" ); document.write( "\n" ); document.write( "y = # of sausage pizzas sold\r
\n" ); document.write( "\n" ); document.write( "z = # of cheese pizzas sold\r
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\n" ); document.write( "\n" ); document.write( "First, translate the sentences to get the following system:\r
\n" ); document.write( "\n" ); document.write( "\"system%28x%2By%2Bz=600%2C12x%2B10y%2B8z=5900%2Cz=y%2B175%29\"\r
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\n" ); document.write( "\n" ); document.write( "Next, transfer the coefficients and the constants to form the augmented matrix:\r
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\n" ); document.write( "\n" ); document.write( "\"%28matrix%283%2C4%2C1%2C1%2C1%2C600%2C12%2C10%2C8%2C5900%2C0%2C-1%2C1%2C175%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's perform the row reduction to solve for x, y, and z (rref steps provided by The Linear Algebra Toolkit):\r
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\n" ); document.write( "\n" ); document.write( "Since the last column has the values 225, 100, and 275, this means that \"x=225\", \"y=100\", and \"z=275\"\r
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\n" ); document.write( "\n" ); document.write( "So the students sold 225 pepperoni pizzas, 100 sausage pizzas, and 275 cheese pizzas.\r
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