document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=190626>Question 190626</A>: <I><SPAN STYLE=\"word-break: break-all;\">  how do i solve this problem... 1. Bob has 60 coins consisting of quarters and dimes. The coins combined value is<BR>\n" );
document.write( "$9.45. Find out how many of each quarters and dimes Bob has. please show me the steps on sloving this... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143107 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143107\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. Bob has 60 coins consisting of quarters and dimes. The coins combined value is<BR>\n" );
document.write( "$9.45. Find out how many of each quarters and dimes Bob has.<BR>\n" );
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document.write( "Q + D = 60 (60 coins)<BR>\n" );
document.write( "25Q + 10D = 945 (total value)<BR>\n" );
document.write( "Q = 60 - D (from 1st eqn)<BR>\n" );
document.write( "Sub into 2nd eqn<BR>\n" );
document.write( "25*(60-D) + 10D = 945<BR>\n" );
document.write( "1500 - 25D + 10D = 945<BR>\n" );
document.write( "-15D = - 555<BR>\n" );
document.write( "D = 37<BR>\n" );
document.write( "Q = 23<BR>\n" );
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