document.write( "Question 190626: how do i solve this problem... 1. Bob has 60 coins consisting of quarters and dimes. The coins combined value is
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Algebra.Com's Answer #143106 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"Bob has 60 coins consisting of quarters and dimes\" translates to \"d%2Bq=60\". Solve for \"q\" to get \"q=60-d\". Let's call this equation 1.\r
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\n" ); document.write( "\n" ); document.write( "Also, \"The coins combined value is $9.45\" translates to \"0.1d%2B0.25q=9.45\"\r
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\n" ); document.write( "\n" ); document.write( "Now multiply EVERY term of the last equation by 100 to make every number a whole number to get: \"10d%2B25q=945\" Let's call this equation 2.\r
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\n" ); document.write( "\n" ); document.write( "\"10d%2B25q=945\" Start with the second equation.\r
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\n" ); document.write( "\n" ); document.write( "\"10d%2B25%2860-d%29=945\" Plug in \"q=60-d\"\r
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\n" ); document.write( "\n" ); document.write( "\"10d%2B1500-25d=945\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"-15d%2B1500=945\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-15d=945-1500\" Subtract \"1500\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-15d=-555\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"d=%28-555%29%2F%28-15%29\" Divide both sides by \"-15\" to isolate \"d\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=37\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So there are 37 dimes\r
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\n" ); document.write( "\n" ); document.write( "\"q=60-d\" Go back to the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"q=60-37\" Plug in \"d=37\"\r
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\n" ); document.write( "\n" ); document.write( "\"q=23\" Subtract\r
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\n" ); document.write( "\n" ); document.write( "So there are 23 quarters\r
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