document.write( "Question 190594This question is from textbook
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document.write( ": Select any imaginary number (of the form \"a + bi,\" where a and b are non-zero real numbers), and another number such that the sum, difference, product, or quotient of the two numbers is a real number.\r
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document.write( "Am very lost here. Thanks! \n" );
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Algebra.Com's Answer #143086 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! It turns out that ANY number of the form \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So adding ANY complex number to it's complex conjugate results in a real number.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Example:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's pick the number \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In short \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note: it turns out that multiplying a complex number by it's complex conjugate also results in a real number (division is a different story however).\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |