document.write( "Question 190594This question is from textbook
\n" ); document.write( ": Select any imaginary number (of the form \"a + bi,\" where a and b are non-zero real numbers), and another number such that the sum, difference, product, or quotient of the two numbers is a real number.\r
\n" ); document.write( "\n" ); document.write( "Am very lost here. Thanks!
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Algebra.Com's Answer #143086 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
It turns out that ANY number of the form \"a%2Bbi\" added to it's complex conjugate of the form \"a-bi\" is \r
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\n" ); document.write( "\n" ); document.write( "\"%28a%2Bbi%29%2B%28a-bi%29=%28a%2Ba%29%2B%28bi-bi%29=2a%2B0i=2a\"\r
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\n" ); document.write( "\n" ); document.write( "So adding ANY complex number to it's complex conjugate results in a real number.\r
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\n" ); document.write( "\n" ); document.write( "Example:\r
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\n" ); document.write( "\n" ); document.write( "Let's pick the number \"2%2B3i\" (where a = 2 and b = 3) and add it to it's complex conjugate \"2-3i\" to get\r
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\n" ); document.write( "\n" ); document.write( "\"%282%2B3i%29%2B%282-3i%29=%282%2B2%29%2B%283i-3i%29=4%2B0i=4\"\r
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\n" ); document.write( "\n" ); document.write( "In short \"%282%2B3i%29%2B%282-3i%29=4\"\r
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\n" ); document.write( "\n" ); document.write( "Note: it turns out that multiplying a complex number by it's complex conjugate also results in a real number (division is a different story however).\r
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