document.write( "Question 190619: The perimeter of a rectangle, given that the length is x yards and the width is 10 yards shorter? \n" ); document.write( "
Algebra.Com's Answer #143082 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"P=2L%2B2W\" Start with the formula for the perimeter for a rectangle\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"P=2x%2B2%28x-10%29\" Plug in the length \"x\" and the width x-10 (since the width is 10 yards shorter than the length)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"P=2x%2B2x-20\" Distribute\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"P=4x-20\" Combine like terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the equation for the perimeter is \"P=4x-20\"
\n" ); document.write( "
\n" );