document.write( "Question 190609: # 1. Use inductive reasoning to determine the next three numbers in the pattern: 1, 1/3, 1/9, 1/27, ... \n" ); document.write( "
Algebra.Com's Answer #143068 by jim_thompson5910(35256)\"\" \"About 
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# 1 \r
\n" ); document.write( "\n" ); document.write( "Q: Use inductive reasoning to determine the next three numbers in the pattern: 1, 1/3, 1/9, 1/27, ... \r
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\n" ); document.write( "\n" ); document.write( "From the first term 1 to the second term \"1%2F3\", notice how the second term is just the first term divided by 3. So let's see if this holds from the second term to the third term.\r
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\n" ); document.write( "\n" ); document.write( "If we divide \"1%2F3\" by \"3\", we get: \"%281%2F3%29%2F3=%281%2F3%29%281%2F3%29=1%2F%283%2A3%29=1%2F9\"\r
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\n" ); document.write( "\n" ); document.write( "So this shows that if we divide \"1%2F3\" by \"3\", we get \"1%2F9\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's divide \"1%2F9\", by \"3\" to get:\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F9%29%2F3=%281%2F9%29%281%2F3%29=1%2F%289%2A3%29=1%2F27\"\r
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\n" ); document.write( "\n" ); document.write( "So dividing \"1%2F9\" by \"3\" gets us \"1%2F27\"\r
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\n" ); document.write( "\n" ); document.write( "So using inductive reasoning, we would conjecture that this pattern continues indefinitely. \r
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\n" ); document.write( "\n" ); document.write( "So this means that we can find the next three terms by dividing each previous term by 3.\r
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\n" ); document.write( "\n" ); document.write( "So divide \"1%2F27\" by 3 to get \r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F27%29%2F3=%281%2F27%29%281%2F3%29=1%2F%2827%2A3%29=1%2F81\"\r
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\n" ); document.write( "\n" ); document.write( "So the next term is \"1%2F81\"\r
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\n" ); document.write( "\n" ); document.write( "Now divide \"1%2F81\" by 3 to get \r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F81%29%2F3=%281%2F81%29%281%2F3%29=1%2F%2881%2A3%29=1%2F243\"\r
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\n" ); document.write( "\n" ); document.write( "So the next term is \"1%2F243\"\r
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\n" ); document.write( "\n" ); document.write( "So divide \"1%2F243\" by 3 to get \r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F243%29%2F3=%281%2F243%29%281%2F3%29=1%2F%28243%2A3%29=1%2F729\"\r
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\n" ); document.write( "\n" ); document.write( "So the next term is \"1%2F729\"\r
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\n" ); document.write( "\n" ); document.write( "So the next three terms of the sequence are \"1%2F81\", \"1%2F243\", and \"1%2F729\"\r
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