document.write( "Question 190589: can you pleaseee help me!!
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\n" ); document.write( "\n" ); document.write( "\"c%2Fb-c%2Fabc\"
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Algebra.Com's Answer #143057 by jim_thompson5910(35256)\"\" \"About 
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\"c%2Fb-c%2F%28abc%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28c%2Aac%29%2F%28b%2Aac%29-c%2F%28abc%29\" Multiply the first fraction by \"ac%2Fac\" to get the denominators equal\r
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\n" ); document.write( "\n" ); document.write( "\"%28ac%5E2%29%2F%28abc%29-c%2F%28abc%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"%28ac%5E2-c%29%2F%28abc%29\" Combine the fractions\r
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\n" ); document.write( "\n" ); document.write( "\"%28c%28ac-1%29%29%2F%28abc%29\" Factor out the GCF from the numerator\r
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\n" ); document.write( "\n" ); document.write( "\"%28cross%28c%29%28ac-1%29%29%2F%28ab%2Across%28c%29%29\" Cancel out like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"%28ac-1%29%2F%28ab%29\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So \"c%2Fb-c%2F%28abc%29=%28ac-1%29%2F%28ab%29\" where \"a%3C%3E0\", \"b%3C%3E0\" or \"c%3C%3E0\"
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