document.write( "Question 190587: #13 i have tired ti figure this out but I do not know where to start\r
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document.write( "A discount store sold plastic cups for 3.50 and each ceramic cups for 4 dollars each. If 400 cups were sold for a total of $1,458, how many cups of each type were sold ? what is the dollar value of each type of cup sold\r
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Algebra.Com's Answer #143054 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A discount store sold plastic cups for 3.50 and each ceramic cups for 4 dollars each. If 400 cups were sold for a total of $1,458, how many cups of each type were sold ? what is the dollar value of each type of cup sold \n" ); document.write( "------------------------------------------- \n" ); document.write( "Equations: \n" ); document.write( "Quantity: p + c = 400 \n" ); document.write( "Value: 3.5p +4c = 1458 \n" ); document.write( "---------------------------- \n" ); document.write( "Multiply thru the 1st equation by 4 to set up the system for elimination: \n" ); document.write( "4p + 4c = 1600 \n" ); document.write( "3.5p+4c = 1458 \n" ); document.write( "-------------------- \n" ); document.write( "Subtract 2nd Eq. from 1st to get: \n" ); document.write( "0.5p= 142 \n" ); document.write( "p = 284 (# of plastic cups sold) \n" ); document.write( "dollar value = 3.5*284 = $994.00 \n" ); document.write( "-------------------- \n" ); document.write( "Substitute into p+c=400 to solve for \"c\": \n" ); document.write( "284 + c = 400 \n" ); document.write( "c = 116 (# of ceramic cups sold) \n" ); document.write( "dollar value = $464\r \n" ); document.write( "\n" ); document.write( "===================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |