document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=190580>Question 190580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could I have some help on the following problem, can't seem to solve. The hypotenuse of a triangle is 10ft long. The longer one is two feet longer than the other. Find the length of the shorter leg. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143048 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143048\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the length of the shorter leg, then the longer leg is x+2.<BR>\n" );
document.write( "Using the Pythagorean theorem <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c%5E2+=+a%5E2%2Bb%5E2 ALIGN=MIDDLE  ALT=\"c%5E2+=+a%5E2%2Bb%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, we can write:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10%5E2+=+x%5E2%2B%28x%2B2%29%5E2 ALIGN=MIDDLE  ALT=\"10%5E2+=+x%5E2%2B%28x%2B2%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplifying, we get:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=100+=+2x%5E2%2B4x%2B4 ALIGN=MIDDLE  ALT=\"100+=+2x%5E2%2B4x%2B4\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtracting 100 from both sides and rearranging, we have:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2%2B4x-96+=+0 ALIGN=MIDDLE  ALT=\"2x%5E2%2B4x-96+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > This can be factored into...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%28x%5E2%2B2x-48%29+=+0 ALIGN=MIDDLE  ALT=\"2%28x%5E2%2B2x-48%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >  so...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B2x-48+=+0 ALIGN=MIDDLE  ALT=\"x%5E2%2B2x-48+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Factor this into...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-6%29%28x%2B8%29+=+0 ALIGN=MIDDLE  ALT=\"%28x-6%29%28x%2B8%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Applying the zero product rule...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x-6+=+0 ALIGN=MIDDLE  ALT=\"x-6+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2B8+=+0 ALIGN=MIDDLE  ALT=\"x%2B8+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > so that...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+6 ALIGN=MIDDLE  ALT=\"x+=+6\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-8 ALIGN=MIDDLE  ALT=\"x+=+-8\"   DISABLED_style= \"max-width:90%; height:auto;\" > Discard the negative solution as lengths are positive quantities.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+6 ALIGN=MIDDLE  ALT=\"x+=+6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The shorter leg is 6 feet. </SPAN>\n" );
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