document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=190409>Question 190409</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An alloy of silver and gold is recast with an addition of silver.  The first alloy is 80 oz, 10 oz. is gold.  If the new alloy is to have only 1/5 oz of gold in every 5 oz. how much silver must be added? \r<BR>\n" );
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document.write( "I am really having trouble with this.  Would you please help?  Thanks so much.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143039 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143039\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Let x=amount of silver that needs to be added\r<BR>\n" );
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document.write( "Amount of gold before silver is added=amount of gold after silver is added;<BR>\n" );
document.write( "so our equation to solve is:\r<BR>\n" );
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document.write( "10=(1/25)(80+x)  \r<BR>\n" );
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document.write( "(Where does the 1/25 come from?  Well 1/5 oz of gold for every 5 oz of alloy is the same as 1/25 oz of gold for every oz of alloy and we have 80+x ounces of alloy)---but we could, as well, write the equation as follows:<BR>\n" );
document.write( "10=(1/5)((80+x)/5)\r<BR>\n" );
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document.write( "Multiply each side by 25\r<BR>\n" );
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document.write( "250=80+x  subtract 80 from each side<BR>\n" );
document.write( "x=170 oz --------------amount of silver that needes to be added\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "10=(1/25)(80+170)<BR>\n" );
document.write( "10=(1/25)(250)<BR>\n" );
document.write( "10=10\r<BR>\n" );
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document.write( "Hope this helps----ptaylor </SPAN>\n" );
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