document.write( "Question 190494: can you help me please.the cost of 20 books is $85.00.some of the books cost $8.00 each and the others cost $3.00 each.how many of each type were bought? \n" ); document.write( "
Algebra.Com's Answer #143036 by jonvaliente(64)![]() ![]() You can put this solution on YOUR website! Let x=no of $8-book \n" ); document.write( ". y=no of $3-book \n" ); document.write( ". \n" ); document.write( "We know that there were 20 books, so: \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Also, we know that the cost of all the books is $85, so: \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Let's multiply (1) by 3 to get: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Let's subtract this new equation from (2) to get: \n" ); document.write( " \n" ); document.write( "- \n" ); document.write( "=============== \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Dividing both sides by 5 we get: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now we know that there were 5 8-dollar books and 20-5=15 3-dollar books. \n" ); document.write( ". \n" ); document.write( "To check: \n" ); document.write( "5*8+15*3=?85 \n" ); document.write( "40+45=?85 \n" ); document.write( "85=85 \n" ); document.write( " |