document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=190555>Question 190555</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a world problem, not sure if I solved it correctly. Could I have some help, thank you. A picture frame is 14cm by 18cm. There are 192cm2 of the picture showing. Find the width of the frame. I have 2cm. Is this correct. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #143007 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=143007\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "Let x = width of frame<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(14-2x)(18-2x) = 192<BR>\n" );
document.write( "(14-2x)(18-2x) = 192<BR>\n" );
document.write( "252 - 28x -36x + 4x^2 = 192<BR>\n" );
document.write( "252 - 64x + 4x^2 = 192<BR>\n" );
document.write( "4x^2 - 64x + 252 = 192<BR>\n" );
document.write( "4x^2 - 64x + 60 = 0<BR>\n" );
document.write( "x^2 - 16x + 15 = 0<BR>\n" );
document.write( "(x-15)(x-1) = 0<BR>\n" );
document.write( "x = {1,15}<BR>\n" );
document.write( ".<BR>\n" );
document.write( "We can toss out the 15 leaving us with:<BR>\n" );
document.write( "x = 1 cm<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );