document.write( "Question 26450: How to i write an equation for each relation. I need help on HOW to find the solution.\r
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document.write( "x 1 2 3 4 5
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document.write( "f(x) 5 7 9 11 13\r
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document.write( "can you help me learn the steps. \n" );
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Algebra.Com's Answer #14295 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! sequences like this are easy to do, once you have the step in your head that i am going to show you... the Jon sure-fire method :-)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Look at the F(x) values...notice their increment is by 2 each time. This is the 2times table... 2, 4, 6, 8, 10, just moved a bit.\r \n" ); document.write( "\n" ); document.write( "So, the x2 table is 2n where n is 1,2,3,4,5, etc\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First term... is 5. First term of the x2 table is 2. How do we get from 2 to 5? by adding 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So formula is 2n+3.. check with say 5th term: 2(5)+3 is 10+3 --> 13. This is the correct value!\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Another \n" ); document.write( "2 5 8 11 14.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Difference is 3..so x3 table ie 3n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First term is 2... x3 table has 3. How do we get from 3 to 2? subtracting 1. So formula is 3n-1. Check say 5th term... Done!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Does that help?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |