document.write( "Question 190473: a manufacturing company has to assign 6 digit lot numbers to its products using A-Z & 0-9, but the first dizit can not be a zero and the last two digits can not be alphabets(A-Z). so how many lot numbers can it produce? \n" ); document.write( "
Algebra.Com's Answer #142948 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "There are 26 alphabetic characters A - Z and 10 numbers, 0 - 9.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since you cannot use zero for the first digit, there are 26 + 9 = 35 ways to choose the first digit.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The second, third, and fourth digits can be anything, so there are 26 + 10 = 36 ways to choose each of those.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And the fifth and sixth position can only be alphabetic, so you only have 26 ways to choose each of the last two digits.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So for each of the 35 ways to choose the first digit, there are 36 ways to choose the second digit, so 35 X 36 = 1260 ways to choose the first two digits. For each of those ways there are 36 ways to choose the third digit...and so on, so:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can operate a calculator as well as I can.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |