document.write( "Question 190428: I need some help with solving direct and indirect variations.
\n" ); document.write( "The problem I have is how to set them up.
\n" ); document.write( "The problem is:
\n" ); document.write( "The volume of gas at a constant temperature varies inversely as the pressure. Find the volume of a gas under pressure of 24 pound per cubic centimeter if the gas occupies a volume of 123 cubic centimeters under a pressure of 20 pounds per cubic centimeter.\r
\n" ); document.write( "\n" ); document.write( "I know i need to use the formula
\n" ); document.write( "Q=k/m but I am not quite sure what goes where.
\n" ); document.write( "Thanks in advance for any help.
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Algebra.Com's Answer #142920 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Ok, you've got the formula in which Q = volume and m = pressure, and k, of course, is the constant of variation.
\n" ); document.write( "You are given that a volume of gas under a pressure (m) of 20 pounds per cu.cm occupies a volume (Q) of 123 cu.cm of gas. Using these values, you can find the value of k in the formula:
\n" ); document.write( "\"Q+=+k%2Fm\" Substitute Q = 123 and m = 20.
\n" ); document.write( "\"123+=+k%2F20\" so that...
\n" ); document.write( "\"k+=+20%28123%29\"
\n" ); document.write( "\"k+=+2460\" Now the formula looks like this:
\n" ); document.write( "\"Q+=+2460%2Fm\" Substitute m = 24 pounds per cu.cm. to find the volume Q.
\n" ); document.write( "\"Q+=+2460%2F24\"
\n" ); document.write( "\"highlight%28Q+=+102.5%29\"cu.cm.
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