document.write( "Question 190386This question is from textbook algebra for college students
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document.write( ": Bob invested some money at 5% simple interest and some at 9% simple interest. The amount invested at the higher rate was twice the amount invested at the lower rate. If the total interst on the investments for 1 year was $920, then how much did he invest at each rate?\r
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document.write( "I know what the answer is but I have tried every forumla and can't figure out where the numbers come from. The anser is $4000 @ 5% and $8000 @ 9%. Your help is greatly appreciated! \n" );
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Algebra.Com's Answer #142882 by jojo14344(1513)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "Let x = amount inv. @ 5% \n" ); document.write( "And, 2x = amount for 9% (twice that of lower rate 5%)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then it follows, \n" ); document.write( "Interest on 5% + Interest on 9% = $920 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x = $4,000.00 , amount for 5%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, 2*($4,000) = $8,000.00 , amount for 9%\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's check, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thank you, \n" ); document.write( "Jojo \n" ); document.write( " |