document.write( "Question 190365: # 3. Bob wants to have concrete driveway in front of his house. The driveway will measure 58 2/3 feet long and 18 1/2 feet wide; and will be 3/4 foot thick. How many cubic yards of cement will be needed for the driveway? Round your answer to the nearest cubic yard. [1 cubic yd = 27 cubic feet]\r
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Algebra.Com's Answer #142870 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
# 3 \r
\n" ); document.write( "\n" ); document.write( "Q: Bob wants to have concrete driveway in front of his house. The driveway will measure 58 2/3 feet long and 18 1/2 feet wide; and will be 3/4 foot thick. How many cubic yards of cement will be needed for the driveway? Round your answer to the nearest cubic yard. [1 cubic yd = 27 cubic feet]\r
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\n" ); document.write( "\n" ); document.write( "A: \r
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\n" ); document.write( "\n" ); document.write( "First, we need to convert all of the mixed fractions to improper fractions.\r
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\n" ); document.write( "\n" ); document.write( "So let's convert \"58%262%2F3\" into an improper fraction\r
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\n" ); document.write( "\n" ); document.write( "\"58%262%2F3\" Start with the first fraction\r
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\n" ); document.write( "\n" ); document.write( "\"58%2B2%2F3\" Break up the mixed fraction into a sum of the whole part and the fraction part.\r
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\n" ); document.write( "\n" ); document.write( "\"58%283%2F3%29%2B2%2F3\" Multiply 58 by \"3%2F3\" (to get equal denominators)\r
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\n" ); document.write( "\n" ); document.write( "\"174%2F3%2B2%2F3\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"%28174%2B2%29%2F3\" Add the fractions\r
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\n" ); document.write( "\"176%2F3\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So \"58%262%2F3=176%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's convert \"18%261%2F2\" into an improper fraction\r
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\n" ); document.write( "\n" ); document.write( "\"18%261%2F2\" Start with the second fraction\r
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\n" ); document.write( "\n" ); document.write( "\"18%2B1%2F2\" Break up the mixed fraction into a sum of the whole part and the fraction part.\r
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\n" ); document.write( "\n" ); document.write( "\"18%282%2F2%29%2B1%2F2\" Multiply 18 by \"2%2F2\" (to get equal denominators)\r
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\n" ); document.write( "\n" ); document.write( "\"36%2F2%2B1%2F2\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"%2836%2B1%29%2F2\" Add the fractions\r
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\n" ); document.write( "\n" ); document.write( "\"37%2F2\" Add\r
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\n" ); document.write( "\n" ); document.write( "So \"18%261%2F2=37%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "So the length and width as improper fractions are \"176%2F3\" and \"37%2F2\". In other words, \"L=176%2F3\" and \"W=37%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Now remember, the volume of a rectangular block is \r
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\n" ); document.write( "\n" ); document.write( "\"V=LWH\" where L is the length, W is the width, and H is the height\r
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\n" ); document.write( "\n" ); document.write( "\"V=%28176%2F3%29%2837%2F2%29%283%2F4%29\" Plug in \"L=176%2F3\", \"W=37%2F2\" and \"H=3%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"V=%28176%2A37%2A3%29%2F%283%2A2%2A4%29\" Combine the fractions (note: just multiply the corresponding numerators and denominators)\r
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\n" ); document.write( "\n" ); document.write( "\"V=%2822%2A2%2A4%2A37%2A3%29%2F%283%2A2%2A4%29\" Factor \"176\" into \"176=88%2A2=22%2A2%2A4\"\r
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\n" ); document.write( "\n" ); document.write( " Cancel out the common terms.\r
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\n" ); document.write( "\n" ); document.write( "\"V=22%2A37\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"V=814\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So the volume of the concrete driveway is 814 cubic feet.\r
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\n" ); document.write( "\n" ); document.write( "Now since we're given the equation\r
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\n" ); document.write( "\n" ); document.write( "1 cubic yard = 27 cubic feet\r
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\n" ); document.write( "\n" ); document.write( "we can multiply the figure 814 cubic feet by the fraction \r
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\n" ); document.write( "\n" ); document.write( "So...\r
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\n" ); document.write( "\n" ); document.write( "Now round to the nearest whole number to get 30 cubic yards\r
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\n" ); document.write( "\n" ); document.write( "So Bob will need 30 cubic yards of cement to build the driveway.
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