document.write( "Question 190317This question is from textbook algebra and trigonometry structure and method book 2
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document.write( ": The stretch on a wire under a given tension varies directly as the length of the wire and inversely as the square of its diameter. A wire having length 2m and diameter 1.5mm stretches 1.2 mm. If a second wire of the same material(and under the same tension) has length 3m and diameter 2.0mm, find the amount of stretch.\r
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document.write( "Please help as i keep on messing the decimals up and can't seem to get the right answer. Please explain also. thank you! \n" );
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Algebra.Com's Answer #142837 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The stretch on a wire under a given tension varies directly as the length of the wire and inversely as the square of its diameter. \n" ); document.write( "stretch = k[L/d^2] \n" ); document.write( "------------------------------\r \n" ); document.write( "\n" ); document.write( " A wire having length 2m and diameter 1.5mm stretches 1.2 mm. \n" ); document.write( "1.2 = k[2/1.5^2] \n" ); document.write( "1.2 = k[8/9] \n" ); document.write( "k = (9/8)1.2 \n" ); document.write( "k = 27/20 \n" ); document.write( "So the equation for your problem is stretch = (27/20)[L/d^2] \n" ); document.write( "---------\r \n" ); document.write( "\n" ); document.write( " If a second wire of the same material(and under the same tension) has length 3m and diameter 2.0mm, find the amount of stretch. \n" ); document.write( "stretch = (27/20)[3/2^2] = 1.0125 \n" ); document.write( "===================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------------------- \n" ); document.write( " |