document.write( "Question 190307: Lynn invested some money at 8%, and then invested $3000 more than twice this amount at 9%. His total annual income from the two investments was $3390. How much was invested at 9%? \n" ); document.write( "
Algebra.Com's Answer #142832 by jojo14344(1513)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "Let x -----> amount inv. at 8% \n" ); document.write( "Also, twice this amount = 2x plus $3,000 = 2x + $3,000 -----> amount inv. at 9%\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then, Income on 8% + Income on 9% = $3,390\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x = $12,000 amount inv. at 8%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thank you, \n" ); document.write( "Jojo \n" ); document.write( " |