document.write( "Question 190307: Lynn invested some money at 8%, and then invested $3000 more than twice this amount at 9%. His total annual income from the two investments was $3390. How much was invested at 9%? \n" ); document.write( "
Algebra.Com's Answer #142832 by jojo14344(1513)\"\" \"About 
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\n" ); document.write( "Let x -----> amount inv. at 8%
\n" ); document.write( "Also, twice this amount = 2x plus $3,000 = 2x + $3,000 -----> amount inv. at 9%\r
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\n" ); document.write( "\n" ); document.write( "Then, Income on 8% + Income on 9% = $3,390\r
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\n" ); document.write( "\n" ); document.write( "\"0.08x%2B0.09%282x%2B3000%29=3390\"
\n" ); document.write( "\"0.08x%2B0.18x%2B270=3390\"
\n" ); document.write( "\"0.26x=3390-270=3120\"
\n" ); document.write( "\"cross%280.26%29x%2Fcross%280.26%29=cross%283120%2912000%2Fcross%280.26%29\"
\n" ); document.write( "x = $12,000 amount inv. at 8%\r
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\n" ); document.write( "\n" ); document.write( "Therefore,
\n" ); document.write( "\"2%2Ahighlight%2812000%29%2B3000=24000%2B3000\"= $27,000, amount inv. at 9% (Answer)\r
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\n" ); document.write( "\n" ); document.write( "Check,
\n" ); document.write( "\"0.08%2812000%29%2B0.09%2827000%29=3390\"
\n" ); document.write( "\"960%2B2430=3390\"
\n" ); document.write( "\"3390=3390\"\r
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\n" ); document.write( "\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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