document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=190308>Question 190308</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a right triangle, one acute angle is 54° more than twice the other. Find each acute angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #142826 by </B><A HREF=/tutors/aboutme.mpl?userid=orca><B>orca(409)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=orca><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=142826\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x represent the smaller angle.<BR>\n" );
document.write( "Then the larger one is 2x + 54.\r<BR>\n" );
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document.write( "As the sum of the measures of the two angles is 90, we have <BR>\n" );
document.write( "x + 2x + 54 = 90\r<BR>\n" );
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document.write( "Solving for x, we have<BR>\n" );
document.write( "3x + 54 = 90<BR>\n" );
document.write( "3x = 90-54<BR>\n" );
document.write( "3x = 36<BR>\n" );
document.write( "x = 12<BR>\n" );
document.write( "So the smaller angle is 12 degrees<BR>\n" );
document.write( "The larger one is 2x + 54 = 2x12 + 54 = 78 degrees<BR>\n" );
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